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The mass of the Earth is `6xx10^(24)kg`. The distance between the Earth and the sun is `1.5xx10^(11)m`. If the gravitational force between the two is `3.5xx10^(22)N` what is the mass of the sun? `G=6.7xx10^(-11) Nm^(2)//kg^(2)` |
Answer» Given `m_(1)=6xx10^(24)kg` `r=1.5xx10^(11)m` `F=3.5x10^(22)N` `G=6.7xx10^(-1)Nm^(2)//kg^(2)` To find `: m_(2)=?` Formula `F=(Gm_(1)m_(2))/(r^(2))` Solution: `(Fr^(2))/(Gm_(1))=m_(2)` `m_(2)=(3.5xx10^(22)xx(1.5xx10^(11))^(2))/(6.7x10^(-11)xx6xx10^(24))` `=(7.875xx10^(44))/(40.2xx10^(13))` `=7.875/40xx10^(31)` ltbr. `=0.196xx10^(31)kg` `=1.96xx10^(30)kg` The mass of the Sun is `1.96xx10^(30)kg` |
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