1.

The mass of the liquid flowing per second per unit area of cross section of the tupe is proportional to P^(x) and v^(y) where P is the pressure difference and v is the velocity, then the relation between x and y is:

Answer»

`x=y`
`x=-y`
`y^(2)=x`
`y=-x^(2).`

Solution :`(M)/(At)=ML^(-2)T^(-1)=[ML^(-1)T^(-2)]^(x)[L^(1)T^(-1)]^(y)`
`=M^(x)L^(-x+y)T^(-2x-y)`
`x=1`
`-x+y=-2`
`y=-1`
Thus `x=-y.`
Hence CORRECT CHOICE is `(b).`


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