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The mass of the moon is ` (1)/(8)` of the earth but the gravitational pull is ` (1)/(6)` earth It is due to the fact that .A. moon is the satellite of the earthB. the radius of the earth is (8/6) of the moonC. the radius of the earth is `(sqrt(8//6))` of the moonD. the radius of the moon is (6/8) of the earth |
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Answer» Correct Answer - C (c ) `(g_(M))/(g_(E))=((G(M_(E)//8))/(R_(M)^(2)))/((GM_(E))/(R_(E)^(2)))=(R_(E)^(2))/(8R_(M)^(2))`.......(i) where the subscript M and E are for the moon and the earth respectively. Given, `(g_(M))/(g_(E))=(1)/(6)`……(ii) From (i) and (ii), we get `(R_(E)^(2))/(8R_(M)^(2))=(1)/(6) or R_(E)=sqrt((8)/(6))R_(M)` |
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