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The mass of the moon is ` (1)/(8)` of the earth but the gravitational pull is ` (1)/(6)` earth It is due to the fact that .A. moon is the satellite of the earthB. the radius of the earth is `8/6` of the moonC. the radius of the earth is `(sqrt(8//6))` of the moonD. the radius of the moon is `(6//8)` of the earth |
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Answer» Correct Answer - C `(gM)/(g_(E))=((G(M_(E)//8))/(R_(E)^(2)))/((GM_(E))/(R_(E)^(2)))=(R_(E)^(2))/(8R_(M)^(2))..........(i)` Where the subcipts M and E are for the moon and the earth respectively. Given, `(gM)/(g_(E))=1/6........(ii)` From (i) and (ii), we get `(R_(E)^(2))/(8R_(M)^(2))=1/6` or `R_(E)=sqrt(8/6)R_(M)` |
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