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The masses of 11C and 11B are respectively 11.0114 u and 11.0093 u. Find the maximum energy a positron can have in the β+-decay of 11C to 11B. |
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Answer» ''C →''B +β++ v mass of C'' = 11.014u ; mass of B'' = 11.0093u Energy liberated = (11.014 – 11.0093)u = 29.5127 Mev. For maximum K.E. of the positron energy of v may be assumed as 0. Maximum K.E. of the positron is 29.5127 Mev. |
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