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The matallic bob of a simple pendulum has the relative density `rho`. The time period of this pendulum is `T` it the metallic bob is immersed in water the new time period is given byA. `2pisqrt((l)/(ng))`B. `2pisqrt((l)/((1-(1)/(n))g))`C. `2pisqrt((ln)/(g))`D. `2pisqrt((l)/((n-1)g))` |
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Answer» Correct Answer - B As discussed in theory part `T=2pisqrt((l)/(g(1-(rho)/(sigma))))` `rho=`density of liquid `sigma=`density of bob material Given `rho=(sigma)/(n)` hence period is `2pisqrt((l)/(1-((1)/(n))g))` |
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