

InterviewSolution
Saved Bookmarks
1. |
The matrix M=⎡⎢⎣−22−3216−1−20⎤⎥⎦ has eigen values 3, -3, 5. An eigen vector corresponding to the eigen value 5 is [1 2 −1]T. One of the eigen vector of the matrix M3 is |
Answer» The matrix M=⎡⎢⎣−22−3216−1−20⎤⎥⎦ has eigen values 3, -3, 5. An eigen vector corresponding to the eigen value 5 is [1 2 −1]T. One of the eigen vector of the matrix M3 is |
|