1.

The maximum acceleration of a body moving in S.H.M. is a_(0) and maximum velocity is v_(0). The amplitude is given by :

Answer»

`(v_(0)^(2))/(a_(0))`
`(a_(0)^(2))/(v_(0))`
`a_(0).v_(0)`
`(1)/(a_(0).v_(0))`

SOLUTION :`a_(0)=omega^(2)R` and `v_(0)=r omega`.
`:.""(v_(0)^(2))/(a_(0))=(r^(2)omega^(2))/(omega^(2)r)=r`.
THUS correct choice is (a).


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