1.

The maximum amplitude of an amplitude modulated wave is found to be 15V while its minimum amplitude is found to b e 3V. The modulation index is

Answer»

`(3)/(2)`
`(2)/(3)`
`(1)/(2)`
`(1)/(3)`

SOLUTION :Here, `A_(c)+A_(m)=15V`
`A_(c)-A_(m)=3V`
Solving (i) and (ii), we get, `A_(c)=9V,A_(m)=6V`
`therefore` MODULATION index, `mu(A_(m))/(A_(c))=(6)/(9)=(2)/(3)`


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