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The maximum efficiency of a steam engine operating between `110^(@)C` and `25^(@)C`A. `20%`B. `22.2%`C. `25%`D. `30%` |
Answer» Correct Answer - B `eta=(T_(2)-T_(1))/(T_(2))=(383-298)/(383)=0.222` or `eta=22.2%` |
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