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The maximum energy in thermal radiation for a source occurs at wavelength 11xx10^(-5)cm. The temperature of the source is n times the temperature of another source of which the wavelength at maximum energy emission is 5.5xx10^(-5) cm The value of n is : |
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Answer» Solution :Since `lamdamT=b`. `:.""lamda_(1)mT_(1)=lamda_(2)mT_(2)` `rArr11xx10^(-5)xxT_(1)=T_(2)XX5*5xx10^(-5)`. Since `T_(1)=nT_(2)`. `:.""11xxnT_(2)=5*5T_(2)`. `rArr""n=1/2` Hence correct choice is (c ). |
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