InterviewSolution
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InterviewSolution
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The maximum height attained by a projectile is increased by 5%. Keeping the angle of projection constant, what is the percentage increases in horizontal range?A. `5%`B. `10%`C. `15%`D. `20%` |
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Answer» Correct Answer - a If h be the maximum height attained by the projectile then `h=(u^(2)sin^(2) theta)/(2g) or R=(u^(2)sin2 theta)/g` `R/h=(2 sin thetacos theta)/((sin^(2) theta)//2) = 4 coth theta` Therefore `(DeltaR)/R=(Deltah)/h` `:.` Percentage increases in R=percentage increases in `y_(m)=5%` |
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