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The maximum impedance of a 50 ohm transmission line with SWR of 3 is(a) 50/3(b) 3/50(c) 150(d) 450The question was asked in final exam.This interesting question is from Standing Waves and SWR in section Transmission Lines of Electromagnetic Theory

Answer»

The correct option is (c) 150

The explanation: The MAXIMUM impedance is given by the product of the characteristic impedance and the SWR. Thus Zmax = S Zo. On SUBSTITUTING for S = 3 and Zo = 50, we get ZMAX = 3 X 50 = 150 UNITS.



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