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| 1. |
The maximum intensity in Young's double slit experiment is I_0. Distance between the slits is d = 5lamda , where lamdais the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance D=10d ? |
| Answer» SOLUTION :`(I_0)/(2)` | |