1.

The maximum intensity obtained due to the superposition of waves of 'n' coherent source having same intensity I_(0) is ......

Answer»

NI
`(I)/(n)`
`n^(2)I`
`(I)/(n^(2))`

Solution :`I_(max)=I_(1)+I_(2)+2 sqrt(I_(1)I_(2)) cos phi`
`=I_(1)+I_(2)+2 sqrt(I_(1)I_(2)) "" [ :. cosphi=cos theta^(@)=1]`
`=[ sqrt(I_(1))+sqrt(I_(2))]^(2)`
`:.` Due to .n. waves of same intensity.
`I_(max)=[ sqrt(I_(0))+sqrt(I_(0))+sqrt(I_(0)+....]^(2)`
`I_(max)=[nsqrt(I_(0))]^(2)=n^(2)I_(0)`


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