InterviewSolution
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InterviewSolution
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The maximum range of a projectile is 500m. If the particle is thrown up a plane is inclined at an angle of `30^(@)` with the same speed, the distance covered by it along the inclined plane will be:A. `250m`B. `500m`C. `750m`D. `100m` |
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Answer» Correct Answer - b For the maximum range, `theta=45^(@)` `R=(u^(2)sin 2 theta)/g=(u^(2))/g sin 90^(@)=(u^(2))/g` or `500=(u^(2))/g` The distance covered along the inclined plane can be obtain using the equation `v^(2)-u^(2)=2as` or `0-u^(2)=2(-g sin 30^(@))s` or `s=(u^(2))/g=500m` |
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