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The maximum tension in the string of an oscillating pendulum is double of the minimum tension. Find the angular amplitude. |
Answer» Correct Answer - A::C::D The tension in the pendulum is maximum at the mea position and minimum on th extreme postion. `Here `1/2mv^2-0=mgl(1-costheta)` `v^2=2gl(1-costheta)` ……….1 `-Now, T_(ma)=mg+2mg(1-costheta)` `[T=mg+(mv^2/l)]` `Again T_(min)=mgcostheta` According to question `T_(max)=2Tmin` `rarr mg+2mg-2mgcostheta=2mgcostheta` `rarr 3mg=4mgcostheta` `costheta=3/4` `rarr thetas=cos^-1 3/4` |
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