1.

The maximum value of index of refraction of a material of a prism which allows the passage of light through it when the refracting angle of prism is A is :

Answer»

`SQRT(1+sin^(2)a//2)`
`sqrt(1+cos^(2)A//2)`
`sqrt(1+tan^(2)A//2)`
`sqrt(1+cot^(2)A//2)`

SOLUTION :(d) `r_(1) = C, r_(2) = C`
`r_(1) + r_(2) = A`
`2C = A, C = (A)/(2)`
`THEREFORE "" mu = (1)/(sin C) = (1)/(sin((A)/(2)))`
`=sqrt((sin^(2)""(A)/(2)=cos^(2)""(A)/(2))/(sin^(2)""(A)/(2)))=sqrt(1+cot^(2)(A)/(2))`


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