1.

The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.A. `100 s`B. `0.01 s`C. `10 s`D. `0.1 s`

Answer» Correct Answer - B
`Aomega = v_(max)`
`T = (2pi)/(omega) = (2piA)/(v_(max)) = 0.01` sec.


Discussion

No Comment Found

Related InterviewSolutions