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The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.A. (a) `0.01 s`B. (b) `10 s`C. (c ) `0.1s`D. (d) `100s` |
Answer» Correct Answer - A (a) Maximum velocity, `v_(max)=aomega, v_(max)=axx2_(pi)/T` rArr `T=(2pia)/v_(max)=(2xx3.14xx7xx10^(-3))/(4.4)~~0.01 s`, |
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