The maximum velocity of a body undergoing SHM is 0.004 m`s^(-1)` and its acceleration at 0.002 m from the mean position is 0.06 m`s^(-2)`. Find its amplitude and period of vibration. [Hint: Use `v_(m) = aomega^(2)x`numerically.[

The maximum velocity of a body undergoing SHM is 0.004 m`s^(-1)` and i

1.	The maximum velocity of a body undergoing SHM is 0.004 m`s^(-1)` and its acceleration at 0.002 m from the mean position is 0.06 m`s^(-2)`. Find its amplitude and period of vibration. [Hint: Use `v_(m) = aomega^(2)x`numerically.[
Answer» Correct Answer - `2.31xx10^(-2)m,3.63s`

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The maximum velocity of a body undergoing SHM is 0.004 m`s^(-1)` and its acceleration at 0.002 m from the mean position is 0.06 m`s^(-2)`. Find its amplitude and period of vibration. [Hint: Use `v_(m) = aomega^(2)x`numerically.[

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