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The maximum velocity of a particle, excuting simple harmonic motion with an amplitude `7 mm`, is `4.4 m//s` The period of oscillation is.A. `100 s`B. `0.01 s`C. `10 s`D. `0.1 s` |
Answer» Correct Answer - B `Aomega = v_(max)` `T = (2pi)/(omega) = (2piA)/(v_(max)) = 0.01` sec. |
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