1.

The maximum velocity of a particle executing simple harmonic motionwith an amplitude 7 mm is 4.4 m/s. The period of oscillation is :

Answer»

0.01 s
10 s
0.1 s
100 s.

Solution :`V_("MAX")=r omega=r.(2pi)/(T)`
`implies T=(2pi r)/(V_("max."))=2xx(2)/(7)xx(7)/(1000)xx(1)/(4.4)=10^(-2)s`
Thus correct CHOICE is (a).


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