1.

The maximum velocity of a particle performing S.H.M. is 6.28 cm/s. If the length of its path is 8 cm, What is its period ?

Answer»

SOLUTION :`v_max=a OMEGA`
` 6.28=a omega`
`6.28=axx(2xx3.14)/T`
`6.28=axx(2PI)/T`
`T=a=4sec.`


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