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The maximum velocity of a particle performing S.H.M. is 6.28 cm/s. If the length of its path is 8 cm, What is its period ? |
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Answer» SOLUTION :`v_max=a OMEGA` ` 6.28=a omega` `6.28=axx(2xx3.14)/T` `6.28=axx(2PI)/T` `T=a=4sec.` |
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