Saved Bookmarks
| 1. |
The maximum wavelength of Lyman series is .... |
|
Answer» `(4xx1.097xx10^(7))/(3)m` `(1)/(lambda)=R[(1)/(1^(2))-(1)/(n^(2))]` but for MAXIMUM wavelength n=2 `:. lambda_(1)/(lambda_(max))=1.097xx10^(7)[(1)/(1)-(1)/(2^(2))]` `:. lambda_(1)/(lambda_(max))=1.097xx10^(7)[1-(1)/(2^(2))]` `:. lambda_(1)/(lambda_(max))=(3)/(4)xx1.097xx10^(7)m^(-1)` `:. lambda_(max)=(4)/(3xx1.097xx10^(7))` |
|