1.

The mean deviation of the data 3, 10, 10, 4, 7, 10, 5 from the mean is A. 2 B. 2.57 C. 3 D. 3.57

Answer»

Explanation: Mean \(\bar X = \frac{3+10+10+4+7+10+5}{7}\) 

\(\bar X= \frac{49}{7}\) 

\(\bar X = 7\) 

xiDi = |xi - x|
34
103
103
43
70
103
52
Total 18

Mean Deviation = \(\frac{\Sigma d_i}{N}\) 

Mean Deviation = \(\frac{18}{7}\) 

Hence, The MD is 2.57


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