The mean deviation of the data 3,10,10,4,7,10,5 from the mean is(a) 2

1.	The mean deviation of the data 3,10,10,4,7,10,5 from the mean is(a) 2 (b) 2.57 (c)3 (d) 3.57
Answer» Heree, Mean `(M) = (3+10+10+4+7+10+5)/7 = 49/7 = 7` Now, Mean Deviation ` = 1/n sum_(i=1)^n \|x_i-M\|` `=1/7(4+3+3+3+0+3+2) = 18/7 = 2.57` So, mean deviation from the mean is `2.57.`

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The mean deviation of the data 3,10,10,4,7,10,5 from the mean is(a) 2 (b) 2.57 (c)3 (d) 3.57

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