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The mean of 100 numbers observations is 50 and their standardsdeviation is 5. The sum of all squares of all the observations is(a)50,000 (b) 250,000 (c) 252500 (d) 255000 |
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Answer» Here, Mean, `bar X = 50` Standard deviation,`(sigma) = 5` `:.` Variance ` = sigma^2 = 5^2 = 25` `:. 25 = 1/n [sum (x_i^2 - barX^2) ]` Here, `n = 100` `:. 25 = 1/100[sum x_i^2 - 100(50)^2]` `=>2500 = sum x_i^2 - 100(50)^2` `=>sum x_i^2 =250000+2500 =252500` `:. sum x_i^2 = 252500.` |
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