InterviewSolution
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InterviewSolution
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The mean of 100 observation is 50 and their standard deviations is 5. Find the sum of all squares of the observations. |
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Answer» Given, \(\bar{x}=50\), n = 100, σ = 5 We have, \(σ^2=\frac{\sum x_i^2}{n}-(\bar{x})^2\) ⇒ \(\frac{\sum x_i^2}{n}=σ^2+(\bar{x})^2\) ⇒ \(\sum x_i^2=n[σ^2+(\bar{x})^2]\) = 100 [52 + (50)2] = 100 (25 + 2500) = 100 × 2525 = 252500 Hence, the sum of all squares of all the observation in 252500. |
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