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The mean power radiation by an elementary dipole is equal to P_(0). Find the mean space density of energy of the electromagnetic field in vacuum in the far field zone at the point removed from the dipole by a distance r along the perpendicular draws to the dipole's axis. |
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Answer» <P> Solution :From the previous problem.`P_(0) = (8piS_(0)r^(2))/(3)` or `S_(0) = (3P_(0))/(8pi r^(2))` Thus `lt w gt= (S_(0))/(c ) = (3P_(0))/(8pi cr^(2))` (Poynting flux VECTOR is the ENRGY contained is a bx of unit CROSS section and length `c`). |
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