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The mean radius of the orbit of a satellite is `4` times as great as that of the parking orbit of the earth. Then its period of revolution around the earth isA. `4` daysB. `8` daysC. `16` daysD. `96` days |
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Answer» Correct Answer - B `v_(0)=sqrt((GM)/(R+h))` and `T=(2pir)/(v_(0))` |
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