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The measurement of an unknown resistance R is to be carried out using Wheatstone bridge as given in the figure below. Twostudents perform an experiment in two ways. The first students takes R_(2) = 10 Omega and R_(1) = 5 Omega. The other student takes R_(2) = 1000 Omega and R_(1) = 500 Omega. In the standard arm, both take R_(3) = 5 Omega . bothfind R= (R_(2))/(R_(1)) , R_(3) = 10 Omega within errors. |
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Answer» The errors of measurement of the two students are the same. For balanced condition of Wheatstone bridge, `(R_(2))/(R) = (R_(1))/(R_(3)) ` `therefore R = R_(3) xx (R_(2))/(R_(1))` For first student :`R_(1)= 5 Omega , R_(2) = 10 Omega` and `R_(3) = 5 Omega` `therefore R = 5 xx (10)/(5)= 10 Omega` For SECOND student : `R_(1) = 500 Omega , R_(2) = 1000 Omega`, `"" R_(3) = 5 Omega` `therefore R = 5 xx (1000)/(500) = 10 Omega` If` R_(1) and R_(2)` are chosen in such a way that it is of very large then current flowing through galvanometer will be very small HENCE null point can be obtained accurately. |
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