1.

The medians BE and AD of a triangle with vertices `A(0, b), B(0, 0) and C(a, 0) ` are perpendicular to each other, if .A. `b=sqrt(2)a`B. `a=pmsqrt(b)b`C. `b=-sqrt(2)a`D. `a=-2b`

Answer» Correct Answer - B
The coordinate of D and E are (a/2, 0) and (a/2,b/2) respectively.
Now, `m_(1)`=Slope of AD `=(b-0)/(0-a//2)=-(2b)/(a)`
`m_(2)` =Slope of BE `=(b//2-0)/(a//2-0)=(b)/(a)`
Since AD and BE are perpendicular . Therefore,
`m_(1)m_(2)=-1-(2b)/(a)xx(b)/(a)=-1 implies a=pmsqrt(2)b`


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