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The metal cube of side 10 cm is subjected to a shearing stress of `10^(4)Nm^-2`. The modulus of rigidiy if the top of the cube is displaced by 0.05 cm with respect to its bottom isA. `2xx10^6Nm^-2`B. `105Nm^-2`C. `1xx10^(7)Nm^-2`D. `4xx10^5Nm^-2` |
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Answer» Correct Answer - A Here, `l=10cm`,`trianglel=0.05cm` Shearing stress`=10^4Nm^-2` `eta=(sheari ng stress)/(sheari ng strai n)=(10^4))/(0.005)=2xx10^6Nm^-2` |
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