1.

The mid point of line segment joining P ( a, b‐2 ) and Q ( ‐2, 4 ) is R ( 2, ‐3 ) then values of a and b are

Answer»

GIVEN:-

P = (a, b-2) = (x1, y1)

Q = (-2, 4) = (x2, y2)

R = (2, -3) = (x, y)

To FIND:-

VALUE of a and b.

Solution:-

By midpoint formula

•°• x = (x1 + x2)/2

2 = (a + (-2))/2

2 = (a - 2)/2

4 = a - 2

4 + 2 = a

6 = a

And,

y = (y1 + y2)/2

-3 = [(b - 2) + 4]/2

-6 = b - 2 + 4

-6 = b + 2

-6 - 2 = b

-8 = b

The value for a and b are 6 and -8.


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