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The minimum (threshold ) KE of the proton to initiate the nulear reaction "" p+^(7)Lirarr ""^(7)Be+n Givenm_(p)=1.0073 amu,m_(1) =7.0144 amu, m_(Be)=7.0147 amu, m_(0)=1.0087 amu. |
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Answer» `2xx10^(-15) J` `[m_(Be)+m_(a)-m_(p)-m_(Li)]=2.5xx10^(-13)` JOULE |
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