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The minimum value of y=x^2+1

Answer»

Answer:

dy/dx=2x

therefore, y is minimum or maximum at x=O

again d2x/d2y =2 which has a POSITIVE VALUE of 2T x= 0

so at x= 0 y will be minimum

min y = 1

or,

y= x^2+1

now x^2 cannot be negetive

so x^2 has a minimum value of 0

and when x^2 is minimum y is also minimum.

so min Y= 1

please follow me....



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