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The minimum value of y=x^2+1 |
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Answer» Answer: dy/dx=2x therefore, y is minimum or maximum at x=O again d2x/d2y =2 which has a POSITIVE VALUE of 2T x= 0 so at x= 0 y will be minimum min y = 1 or, y= x^2+1 now x^2 cannot be negetive so x^2 has a minimum value of 0 and when x^2 is minimum y is also minimum. so min Y= 1 please follow me.... |
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