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The mode of the following series is 17.3 . Find the missing frequecny : |
Answer» Clearly 15-20 is the modal class as the mode 17.3 lies in this class. Here, `l=15,f_(1)=24,f_(0)=x("say"),f_(2)=17 and h=5 and mode =17.3` `"Mode(M)"=l+(f_(1)-f_(0))/(2f_(1)-f_(0)-f_(2))xxh` `17.3=15+(24-x)/(2xx24-x-17)xx5` `17.3=15+(24-x)/(31-x)xx5` `2.3(31-x)=120=5x` `2.3xx31-2.3x=120-5x` 5x-2.3x=120-17.3 2.7x=4.87 `x=(48.7)/(2.7)=18.03` Hence, missing frequency is 18 |
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