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The modulus of section required for angle section purlin is given by(a) Z = M/(0.66xfy)(b) Z = M/(1.33×0.66xfy)(c) Z = M/(1.33×0.66xfy)(d) Z = M/(1.33xfy)I have been asked this question by my college director while I was bunking the class.This question is from Purlins in section Design of Beams of Design of Steel Structures |
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Answer» Correct CHOICE is (c) Z = M/(1.33×0.66xfy) |
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