The modulus of the vector product of two vectors is (1)/(sqrt(30)) times their scalar product. The angle between vectors is

The modulus of the vector product of two vectors is (1)/(sqrt(30)) tim

1.	The modulus of the vector product of two vectors is (1)/(sqrt(30)) times their scalar product. The angle between vectors is
Answer» `(pi)/(6)` `(pi)/(2)` `(pi)/(4)` `(pi)/(3)` Solution :(a) `ABsintheta=(1)/(SQRT(3))ABcostheta` `:.tantheta=(1)/(sqrt(3))ortheta=30^(@)=(pi)/(6)`

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The modulus of the vector product of two vectors is (1)/(sqrt(30)) times their scalar product. The angle between vectors is

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