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The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should beA. `98.96^(@)C`B. `100.52^(@)C`C. `101.04^(@)C`D. `107.01^(@)C` |
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Answer» Correct Answer - C `DeltaT_(b)=iK_(b)m=2xx1xx0.52=1.04` `:.T_(b)=T_(b)^(@)+DeltaT_(b)=100+1.04` `101.4^(@)C` |
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