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The molality of `1 L` solution with `x% H_(2)SO_(4)` is equal to 9. The weight of the solvent present in the solution is `910 g`. The value of `x` is:A. `90`B. `80.3`C. `40.13`D. `9` |
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Answer» Correct Answer - B `m=(axx1000)/(98xx910)=9` `:. a= 802.62 g//"litre"` `:. %` by weight `=80.26 g=X` |
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