1.

The molar conductivities ofwedge_(NaOAc)^(@) and wedge_(HCl)^(@) at infinite dilution in water at 25^(@)Care 91.0 and 426.2 S cm^(2)//mol respectively. To calculate wedge_(HOAc)^(@), the additional value required is :

Answer»

`wedge_(H_(2)O)^(@)`
`wedge_(KCL)^(@)`
`wedge_(NaOH)^(@)`
`wedge_(NACL)^(@)`

Solution :According to Kohlrausch's LAW:
`Lambda_(CH_3COOH)^(0)=Lambda_(CH_3COONa)^(0)+Lambda_(HCL)^(0)-Lambda_(NaCl)^(0)`


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