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The molar heat capacity in a process of a diatomic gas if it does a work of `Q/4` when a heat of `Q` is supplied to it isA. `(2)/(5) R`B. `(5)/(2) R`C. `(10)/(3) R`D. `(6)/(7) R` |
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Answer» Correct Answer - C `dU = C_(v)dT = (5/2 R) dT or dT = (2(dU))/(5R)` ..(i) From first law of thermodynamics `dU = dQ - dW = Q -Q/4 = (3Q)/(4)`. Now molar heat capacity `C = (dQ)/(dT) = (Q)/((2(dU))/(5R)) = (5RQ)/(2((3Q)/(4))) = 10/3 R`. |
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