1.

The molar heat capacity in a process of a diatomic gas if it does a work of `Q/4` when a heat of `Q` is supplied to it is

Answer» `dU=C_(v)dT=((5)/(2)R)dT ("or")dT=(2)(dU)/(5R)`
From first law of thermodynamics
`dU=dQ-dW=Q-(Q)/(4)=(3Q)/(4)`
Now molar heat capacity
`C=(dQ)/(dT)=(Qxx5R)/(2(dU))=(5RQ)/(2((3Q)/(4)))=(10)/(3)R`


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