1.

The molar specific heat of Ar at constant volume is 12.47 J/mol.K. Two moles of Ar are heated at constant pressure so that the rise in temperature is 20 K. Find the work done by the gas on its surroundings and the heat supplied to the gas. Take R = 8.314 J/mol.K.

Answer»

Data : Cv = 12.47 j/mol.K, n = 2,Tf – Ti = 20 K, 

R = 8.314 J/mol.K

1. W = nR (Tf – Ti) = (2) (8.314) (20) J = 332.6 J

This is the work done by the gas on its surroundings.

2. Q = nCv (Tf – Ti) + W = (2) (12.47) (20) + 332.6

= 498.8 + 332.6 = 831.4 J 

This is the heat supplied to the gas.



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