InterviewSolution
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InterviewSolution
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The molar volume of He at `10 .1325MP` and `273K` is 0.011075 of its molar volume at 101.325 kPa at `273 K` Calculate the radius of helium atom The gas is assumed to show real nature Neglect the value of a for He . |
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Answer» For real gas `[P+(a)/(V^(2))][V -b] =RT` or `P[V -b] =RT` (neglectinga) `:. (10.1325 xx10^(6))/(101325) [V_(1)-b] =0.0821 xx 273` `(101325 Pa = 1atm)` or `100[V_(1)-b] = 0.0821 xx 273 =22.41 ..(1)` `(101.325 xx 10^(3))/(101325) [V_(2)-b] = 0.0821 xx 273` or `[V_(2) -b] =22.41 ...(2)` By eq.`(1) V_(1) = 0.2241 +b ...(3)` By eq (2) `V_(2) = 22.41 +b...(4)` By eqs (3) and `(4) (V_(1))/(V_(2)) = (0.2241 +b)/(22.41 +b)` `(0.011075V_(2))/(V_(2)) = (0.2241+b)/(22.41 +b)` `(V_(1) = 0.011075 V_(2)` is given) `:. b = 0.024 litre mo1^(-1) = 24 cm^(3) mo1^(-1)` `:. b =4N xx upsilon = 4 xx 6.023 xx 10^(23) xx (4)/(3) pi r^(3)` or `24 = 4 xx 6.023 xx 10^(23) xx (4)/(3) xx (22)/(7) xx r^(3)` `:. r = 1.33 xx 10^(-8) cm` . |
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