1.

The molarity of a solution obtained by mixing 800 ml of 0.5 M HCl with 200 ml of 1 M HCl will be

Answer»

0.8 M
0.6 M
0.4 M
0.2 M

SOLUTION :`underset(("Initial"))(M_(1)V_(1))+M_(2)V_(2)=underset(("FINAL"))(M_(3)V_(3))`
`V_(3)=V_(1)+V_(2)=800+200=1000`
`M_(3)xx1000=0.5xx800+1xx200`
`M_(3)=(600)/(1000)=0.6M`.


Discussion

No Comment Found

Related InterviewSolutions