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The mole fraction of glucose (C6 H12 O6 ) in an aqueous binary solution is 0.1. The mass percentage of water in it, to the nearest integer, is ______. |
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Answer» 47 Let total mole is 1 mol then mole of glucose will be 0.1 and mole of water will be 0.9 so mass % of water = (0.9 x 18)/(0.1 x 180 + 0.9 x 18) x 100 = 47.36 = 47 |
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