1.

The molecular formula of ether is:

Answer»

`C_(n)H_(2N)O`
`C_(n)H_(2n+1)O`
`C_(n)H_(2n+2)O`
`C_(n)H_(2n)OC_(n)H_(2n)`

Solution :`C_(2)H_(6)OC_(2)H_(5)-=C_(4)H_(10)O=C_(n)H_(2n+2)O`


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